ok edit. I figured out the yellow numbers mean its in the wrong spot but is one of the combination numbers. What I think might be helpful is if the number is used twice then have it be another color other than yellow. Then at least you have a fighting chance of winning, otherwise the game feels like you got cheated because the very first 2 rounds are always going to be 1234 5678 unless you get lucky on those 2 rows you only get 1, maybe 2 if you're really lucky, guess at the last combo. Otherwise the game is solid and I enjoyed it.
Yea, the wrong spot code baffled me till I ran out of time, but, I don't think you'd ever lose if it didn't work that way. At first I had 5 numbers with 6 lines and you never would lose then I switched to 4 numbers and 5 lines to make it just a little more difficult (sometimes it just ends with a wrong guess at the end), thanks for playing!
I really like the game, but there is also another little thing. If you want to submit your high score you have to lose a round. If you say NO by the CONTINUE? you just get back to the main menu and lose your high score.
indeed, in the "shake" code the animator messes with the flip code I didn't catch that in time and I never thought it would lock up or crash or I would have pulled it, sorry bout that
Logical it's the opposite. If you do it right you should never lose a round by the amount of guesses and only by time.
Use the first two tries to just to get through the nummbers 1-8. Dont repeat anything. If by then you still did not get atleast 4 yellow nummbers. Use the thrid guess to look in to 9 and 0 and already start to try figure out repeatet nummbers. So that in every field was at least a yellow/green number. After that all, should fall in to place.
As a example by the first two guesses i only got a yellow 2 and a yellow 8. For the third guess i put the 2980. So the unsure numbers are under already yellow/green blocks and in the rest i already look for possible repeats.
Because there are only a maximum of three nummbers when they repeat, you should figure in two guesses, per process of elimination, out where the numbers belong.
That sounds easy enough, but I am not able to do it (I figured out that should be the process like the 5th time playing it), but I do not know if it's just that I'm not smart enough. So I request you to play and test whether it is indeed possible to win every time
So to show of a little i put up the high score of 10100. I forcefully finished there. Only thing i can add now is if you got only two colored numbers under each other you must spread the 9 and 0 out over the third and fourth guess. For the fourth guess you want to be sure to always have at least a colored number in every column thats not repeating in the column.
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ok edit. I figured out the yellow numbers mean its in the wrong spot but is one of the combination numbers. What I think might be helpful is if the number is used twice then have it be another color other than yellow. Then at least you have a fighting chance of winning, otherwise the game feels like you got cheated because the very first 2 rounds are always going to be 1234 5678 unless you get lucky on those 2 rows you only get 1, maybe 2 if you're really lucky, guess at the last combo. Otherwise the game is solid and I enjoyed it.
Yea, the wrong spot code baffled me till I ran out of time, but, I don't think you'd ever lose if it didn't work that way. At first I had 5 numbers with 6 lines and you never would lose then I switched to 4 numbers and 5 lines to make it just a little more difficult (sometimes it just ends with a wrong guess at the end), thanks for playing!
I found two bugs with the enter button.
If you hit enter by 3 or less numbers in the row, the game will not reveal the numbers correctly in the top after the missing numbers where entert.
and if you hit enter after already entering a correct row, the game will crash and hardlock. Lost my score of >7000 because of that. ;_;
I really like the game, but there is also another little thing. If you want to submit your high score you have to lose a round. If you say NO by the CONTINUE? you just get back to the main menu and lose your high score.
indeed, in the "shake" code the animator messes with the flip code I didn't catch that in time and I never thought it would lock up or crash or I would have pulled it, sorry bout that
This is beyond tough, if you ever get repeated numbers, there is no hope to figure out the right number in the given number of tries
Logical it's the opposite. If you do it right you should never lose a round by the amount of guesses and only by time.
Use the first two tries to just to get through the nummbers 1-8. Dont repeat anything. If by then you still did not get atleast 4 yellow nummbers. Use the thrid guess to look in to 9 and 0 and already start to try figure out repeatet nummbers. So that in every field was at least a yellow/green number. After that all, should fall in to place.
As a example by the first two guesses i only got a yellow 2 and a yellow 8. For the third guess i put the 2980. So the unsure numbers are under already yellow/green blocks and in the rest i already look for possible repeats.
Because there are only a maximum of three nummbers when they repeat, you should figure in two guesses, per process of elimination, out where the numbers belong.
That sounds easy enough, but I am not able to do it (I figured out that should be the process like the 5th time playing it), but I do not know if it's just that I'm not smart enough. So I request you to play and test whether it is indeed possible to win every time
So to show of a little i put up the high score of 10100. I forcefully finished there. Only thing i can add now is if you got only two colored numbers under each other you must spread the 9 and 0 out over the third and fourth guess. For the fourth guess you want to be sure to always have at least a colored number in every column thats not repeating in the column.
This is the way
Huh, neat. Looks like I have a long way to go